How to write a Web Service which returns JSON object & a client that reads it

We will need a couple of more jars in our classpath in order to use JSON.
They are - jackson-core-asl-1.8.0.jar, jackson-jaxrs-1.8.0.jar, jackson-mapper-asl-1.8.0.jar, jackson-xc-1.8.0.jar, jersey-json-1.8.jar, jersey-bundle-1.8.jar
Download them & add in the class path or add them in pom.xml as a dependency.

Here is the code snippet for the web service which returns JSON Object

@GET

 @Path("/json")

 @Produces(MediaType.APPLICATION_JSON)

 public List<User> getUserDetailsInJsonFromURL

   (@QueryParam("name") String name) {

   User returnUser = new User();

   List<User> returnList = new ArrayList<User>();

   if (name != null && !"".equals(name)) {

   for (int count = 0; count < userList.size(); count++) {

    if (name.equalsIgnoreCase(userList.get(count).getName())) {

     returnUser = userList.get(count);

     returnList.add(returnUser);

    }

   }

  } 

  return returnList;

 }

note: userList is the list which contains the all the user data fetched from database.

And, here is the client which accepts & then processes the JSON result set
(Client needs java-json.jar in it's classpath to develop this code)

public void parseJson(WebResource service)

   throws UniformInterfaceException, JSONException {

  JSONArray resultArray = new JSONArray(service

    .path("resources/test/json/Tom")

    .get(String.class));

  List<User> userList = new ArrayList<User>();

  for (int count = 0; count < resultArray.length(); count++) {

   JSONObject userObject = resultArray.getJSONObject(count);

   User user = new User(userObject.get("name").toString(), userObject

     .get("surname").toString(), 

      userObject.get("address")

     .toString());

   userList.add(user);

  }

  System.out.println(userList);

 }

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Related post -
 Creating RESTful web service with Maven & Jersey
Creating a Simple Web Service Client

"Perplexity is the beginning of the knowledge" - Khalil Gibran