Parsing a XML in Java

What if a web service returns its result in form of XML? like this may be -


It's easy!!

This is the code snippet which is going to do the magic!!

Config config = new DefaultClientConfig();

Client client = Client.create(config);

WebResource service = client.resource(UriBuilder.fromUri("http://localhost:8080/Test")

    .build());

InputSource inputSource = new 

InputSource(new StringReader(service.path(

    "resources/test/Tom").get(String.class)));

DocumentBuilderFactory 

factory = DocumentBuilderFactory.newInstance();

DocumentBuilder builder = factory.newDocumentBuilder();

Document doc = builder.parse(inputSource);

NodeList nameList = doc.getElementsByTagName("name");

NodeList surnameList = doc.getElementsByTagName("surname");

NodeList addressList = doc.getElementsByTagName("address");

System.out.println("No. of result returned : " + nameList.getLength());

List<User> userList = new ArrayList<User>();

for (int count = 0; count < nameList.getLength(); count++) {

   User user = new User(nameList.item(count).getTextContent(),

                 surnameList.item(count).getTextContent(), 

                 addressList.item(count).getTextContent());

   userList.add(user);

  }

System.out.println(userList);

note:

a. Obviously, User is the bean class as mentioned in the previous post.
b.  doc.getElementsByTagName("name") means that we are reading the data from the nodes where the node name is "name"

Related post: A Web Service that returns XML

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